Solubility of substance
The term solubility refers to the maximum amount of material that will dissolve in a given amount of solvent at a given temperature to produce a stable solution.
Examples 1: If 12.2 g of lead(II) trioxonitrate(V) were dissolved in 21 g of distilled water at 20oC, calculate the solubility of the solute in mol dm-3.
Solution:
Molar mass of Pb(NO3)2 = 331 g
12.2 g of Pb(NO3)2 = 12.2/331 = 0.037 mole
21 g of water at 20oC dissolved 0.037 mole of Pb(NO3)2
1000 cm3 of water at 20 oC dissolved 1000 x 0.037 / 21
= 1.76 moles of Pb(NO3)2
At 20oC, the solubility of Pb(NO3)2 in water is 1.76 mol dm-3
Using formula Method
Solubility = mass/molar mass x 1000/vol
= 12.2/331 x 1000/21
= 1.7751 mol dm-3
Read our disclaimer.
AD: Take Free online baptism course: Preachi.com