Categories
Mathematics

Application of Laws of Indices

Solve the following

(i)            32 3/5                                (ii)           343 2/3   (iii) 64 2/3(iv) 0.001            (v) 14 0

Solution:

  1. i) 32 3/5 = (32 1/53 = (5√32) 3

= 2 3 = 8

  1. ii) 343 2/3 = (343 1/3 )2 = (3√343)2

= (7 3)1/3)2

= 72 = 49

iii)           64 2/3 = (64 1/3)2 = (4 3)1/3)2 = 4 2

  1. iv) (0.001)3 = (1/100)3 = (1/10)3)3 = (10 -3)3

= 10 -9 = 1/10 9

  1. v) 14 0 = 1

EVALUATION

1)            Simplify the following

  1. a) 216 4/3 b) 25 5 c) (0.00001)2
  2. d) d 32 2/5    e) 81 ¾

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