WEEK 10 - [A] SIMPLE EQUATION AND VARIATION. [B] CHANGE OF SUBJECT OF FORMULAE. [C] TYPE OF VARIATION; DIRECT, INVERSE, JOINT AND PARTIAL VARIATION. [D] APPLICATIONOF VARIATION TO PRACTICAL PROBLEMS.
Find the original number of the following logarithms numbers:
1027 (b) 100.27 (c) 6.3892
SOLUTION
1027 = 1.862, from antilogarithm table check 27 under zero since there is no third value and the zero before the point (characteristics) determines where the point occupies in the number. Add onto every positive characteristic to determine your value
