SS1 First Term Mathematics Senior Secondary School 10 Sections21 Lessons10 Weeks

Curriculum

10 Sections
21 Lessons
10 Weeks

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WEEK 1 - REVISION AND BASIC OPERATIONS OF INTEGER
3 Items
WEEK 2 - NUMBER BASES /BASE NUMBER
3 Items
WEEK 3 - 1. [A] ADDITION, SUBTRACTION, MULTIPLICATION AND DIVISION OF NUMBER BASES . [B] APPLICATION OF NUMBER BASES TO COMPUTER PROGRAMMING.
1 Item
- 4.1
  Application Of Base Number To Computer Programming
  45 Minutes
week 4 - 1. CONCEPT OF MODULAR ARITHMETIC; ADDITION, SUBTRACTION, MULTIPLICATION AND DIVISION OF OPERATIONS OF MODULAR ARITHMETIC
3 Items
WEEK 5 - STANDARD FORM AND APPROXIMATION
2 Items
- 6.1
  Standard Form And Approximation
  45 Minutes
- 6.2
  Approximation (Significant Figure, Decimal Places And Rounding Off)
  45 Minutes
WEEK 6 - INDICES
2 Items
[a]Application of laws of indices. [b] Negative, zero and fractional indices.
- 7.1
  Basic Laws of Indices
  45 Minutes
- 7.2
  Assessment – Indices
WEEK 7 - REVIEW OF FIRST HALF
0 Items
Review what you have leaernt so far!
WEEK 8 - LOGARITHMS OF NUMBERS GREATER THAN 1 [WHOLE NUMBER]→
3 Items
use of logarithm table for multiplication and division of numbers.
WEEK 9 - LOGARITHMS CTD; [A] CALCULATIONS INVOLVING POWERS AND ROOTS. [B] RELATIONSHIP BETWEEN INDICES AND LOGARITHMS.
2 Items
- 10.1
  Squares Or Powers Of Numbers In Logarithms
  45 Minutes
- 10.2
  Relationship between Indices and Logarithms
  45 Minutes
WEEK 10 - [A] SIMPLE EQUATION AND VARIATION. [B] CHANGE OF SUBJECT OF FORMULAE. [C] TYPE OF VARIATION; DIRECT, INVERSE, JOINT AND PARTIAL VARIATION. [D] APPLICATIONOF VARIATION TO PRACTICAL PROBLEMS.
2 Items
- 11.1
  Simple Equation And Subject of formula
- 11.2
  Variation and Types of Variation
  50 Minutes

Antilogarithm

ANTILOGARITHM: Is the opposite of logarithm.

Find the original number of the following logarithms numbers:

10²⁷ (b) 10^0.27 (c) 6.3892

SOLUTION

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10²⁷ = 1.862, from antilogarithm table check 27 under zero since there is no third value and the zero before the point (characteristics) determines where the point occupies in the number. Add onto every positive characteristic to determine your value
10⁵⁶⁸ = 3698.0 or 3698
3892 = 2450000.0

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SS1 First Term Mathematics Senior Secondary School 10 Sections21 Lessons10 Weeks

Curriculum

Antilogarithm

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