The study of cross involving the inheritance pattern of two characters each of which is
determined by two alleles of a gene for instance, pea plant with seed colour and seed shape are used in garden pea plant , round seed (RR) is dominant over wrinkled seed (rr) , yellow seed (Y) is dominant over the green seed (y).
When a pure stock of plants having round yellow seeds is crossed with a pure stock of wrinkled and seeds, the F1 general offspring all round and yellow.
When a pure stock of plants having round yellow seeds is crossed with a pure stock of wrinkled and seeds , the F1 general offspring all round and yellow.
Parents ____ Round and yellow X wrinkled and green
RYRY x ryry
Gametes RY ry
F1 RYry (All round and yellow)
F2 is arranged in prunnet table as follow
RY, ry , X RYry
Gametes : RY, RY, ry , ry X RY , RY, RY, ry
RY | RY | ry | ry | |
RY | RYRY | RYRY | RYrY | RYrg |
Ry | RyRy | RyrY | RyrY | Ryry |
Ry | RYrY | RyrY | RyrY | rYry |
Ry | RYry | Ryry | rYry | ryry |
Analysis of phenotype ratio
Round and yellow | 9 |
Round and green | 3 |
Wrinkled and yellow | 3 |
Wrinkled and green | 1 |
Analysis of genotyptic ratio
Homozygons romo yellow | 1 |
Homozygons romo green | 1 |
Homozygons wrinkled yellow | 1 |
Homozygons wrinkled green | 1 |
Homozygons Romo, heterozygons yellow | 2 |
Homozygons romo yellow, Homozygons green | 2 |
Homozygons wrinkled, Homozygons yellow | 2 |
Homozygons romo and yellow | 4 |
Questions
(1) A man with heterozygous genotype for blood group B marries a woman with heterozygous
- what percentage of their children be universal donor?
2.The alternative form of a gene that represents constrasting character is a/an (A)allele (B)diploid (C)haploid (D)homologue
(3) If two parents are sickle cell carrier their genotype would be (A) Hb A HbA and Hbs Hbs (b) HbsHbs and Hbs Hbs (c) HbA Hbs and Hb A Hbs (D) Hba HbA and HbA HbA
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