What is the height of a cylindrical iron if the density is 7900kg/m3? The mass is 700kg and the radius is 0.1m.

All QuestionsCategory: Secondary SchoolWhat is the height of a cylindrical iron if the density is 7900kg/m3? The mass is 700kg and the radius is 0.1m.
God's will asked 8 months ago

What is the height of a cylindrical iron if the density is 7900kg/m3? The mass is 700kg and the radius is 0.1m.

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1 Answers
User AvatarStopLearn Team Staff answered 8 months ago

To find the height of a cylindrical iron object given its mass, density, and radius, you can use the formula for the volume of a cylinder:
Volume = π * r² * h
Where:

  • Volume is the total volume of the cylinder.
  • π (pi) is approximately 3.14159.
  • r is the radius of the cylinder.
  • h is the height of the cylinder.

You already have the mass (M) of the object and its density (ρ). The formula to calculate volume from mass and density is:
Volume = Mass / Density
Now, plug in the values you have:
Volume = 700 kg / 7900 kg/m³
Volume = 0.0886 m³
Now, we can set this equal to the formula for the volume of a cylinder and solve for the height (h):
0.0886 m³ = π * (0.1 m)² * h
Now, solve for h:
h = 0.0886 m³ / (π * (0.1 m)²) h ≈ 28.31 meters
So, the height of the cylindrical iron object is approximately 28.31 meters.

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