Estimation of Dimensions and Distances
Estimation is making a guess of the nearly correct calculations and distances, weights, prices or capacity of things without the actual measurements or calculations. Estimations help us to have rough idea of the answer when we add, subtract, multiply or divide any given quantity.
Sometimes rounding off and approximations are used in making an estimation.
Examples of estimations are as follows:
When physical quantities are measured, they need to be expressed in standard units of measurement. A unit is therefore a standard used in the measurement of a physical quantity. These physical quantities are length, mass, time, capacity and even currency.
Distances
This is a linear measure of length. The metric system uses multiples of ten to build up its table measurement. The basic unit of length is metre.
10 millimeter (mm) = 1 centimetre
10 centimeters (cm) = 1 decimetre
10 decimeters (dm) = 1 metre
10 meters (m) = 1 decametre
10 decameters (dam) = 1 hectometre
10 hectometers (hm) = 1 kilometre
The frequently used of them is centimeter (cm), metre (m) and kilometer (km)
Examples:
(i) 12km (ii) 6hm (iii) 324cm
(i) 4580m (ii) 144hm
Solution
(i) 12km to metre
First, 1 km = 1000m
Then, 12km = 12 × 1000 = 12000m
Therefore, 12km = 12000m
(ii) 6hm to metre
But 1hm = 100m
Then, 2.6 hm = 2.6 × 100 = 26
Therefore, 2.6hm = 26m
(iii) 324cm to metre
But 100cm = 1m
Then, 324cm = 324 ÷ 100 = 3.24
Therefore, 324cm = 3.24 m
Now, we convert to kilometre
2 (i) 4850m to kilometre
But 1000m = 1 kilometre
Then, 4850m = 4850 ÷ 1000 = 4.850
Therefore, 4850m = 4.850km
(ii) 144hm to kilometre
10hm = 1 kilometre
Then, 144hm = 144 ÷ 10 = 14.4
Therefore, 144hm = 14.4km
CLASS ACTIVITY:
(i) 2 m (ii) 5km (iii) 9km and 8m
(i) 3800cm (ii) 3000mm (iii) 2km
(i) 12580m (ii) 1250dam (iii) 8420m
The Capacity and Mass of Objects
Capacity of Objects
Capacity is the space that is available to hold something. It is closely related to volume because they are both used to measure space. Volume is actually the space occupied by an object. A cubic measure is the measure of volume and this is illustrated below:
1000 cubic millimetre (mm3) = 1 cubic centimetre (cm3)
1000 cubic centimetre (cm3) = 1 cubic decimetre (dm3)
1000 cubic decimetre (dm3) = 1cubic metre (m3)
Example:
Express the following m3: (i) 3500000cm3 (ii) 1450dm3 (iii) 28000mm3
Solutions:
(i) 3500000cm3 to m3
But 1000cm3 = 1 dm3 and 1000dm3 = 1m3
Therefore, (1000 × 1000) cm3 = 1000000cm3 = 1m3
3500000cm3 = 3500000 ÷ 1000000 = 3.500000m3
Hence, 3500000cm3 = 3.5m3
(ii) 1450dm3 to m3
But 1000dm3 = 1m3
Then, 1450dm3 = 1450 ÷ 1000 = 1.450m3
Hence, 1450dm3 = 1.45m3
(iii) 28000mm3 to m3
But 1000mm3 = 1cm3, 1000cm3 =1dm3 and 1000dm3 = 1m3
Therefore, (1000 × 1000 × 1000) mm3 = 1000000000mm3 = 1m3
28000mm3 = 28000 ÷ 1000000000 = 0.000028000m3
Hence, 28000mm3 = 0.000028000m3
Class Activity: Express the following in m3
(i) 756000cm3 (ii) 65400dm3 (iii) 38500dm3 (iv) 17500cm3 (v) 2580dm3
The unit of capacity is Litre (L), which is equal to one cubic decimetre (i.e 1000cm3 = 1 litre). Its table is given below:
10 millilitres (ml) = 1 centilitre (cl)
1000 millitres = 1litre (l)
100 centilitres = 1 litre
1000 litres = 1m3
Example:
Express each of the following in litres (i) 75ml (ii) 356cl (iii) 5.3m3
Solution:
(i) 75ml to litre
But 1000ml = 1 litre
Therefore, 75ml = 75 ÷ 1000 = 0.075litre
Hence, 75ml = 0.075litre
(ii) 356cl to litre
100cl = 1 litre
Therefore, 356cl = 356 ÷ 100 = 3.56litres
(iii) 5.3m3 to litre
But 1m3 = 1000 litres
Therefore, 5.3m3 = 5.3 × 1000 = 5300litres
Hence, 5.3m3 = 5300 litres.
The Mass of Objects
Mass is the quantity of matter in a body. In the metric system, the kilogram (kg) is the base unit of mass. The table is given below:
1 decagramme (dg) = 10 grams (g)
1 hectogramme (hg) = 100 g
1 kilogramme (kg) = 1 000 g
1 tonne (t) = 1 000 kg
100 centigramme (cg) = 1 g
200 milligrams (mg) = 1 carat
1000 milligramme (mg) = 1 g
Example:
Express each of the following in kilograms
(i) 60 carats (ii) 58 mg (iii) 2.5 tonnes
Solution:
(i) 60 carats to kilogram
1 carat = 200mg = 200 × 1mg
Now, 60 carats = 60 × 200 = 12000mg
But 1000mg = 1gm and 1000g = 1kg
(1000 × 1000) mg = 1000000mg = 1kg
Therefore, 60 carats = 12000 ÷ 1000000 = 0.012kg
Hence, 60 carats = 0.012kg
(ii) 58mg to kilogram
1000mg = 1g and 1g = 1000kg
Therefore, (1000 × 1000) mg = 1000000mg = 1kg
Now, 58mg = 58 ÷ 1000000 = 0.000058kg
Hence, 58mg = 0.000058kg
(iii) 5 tonnes to kilogram
1 tonne = 1000kg
Therefore, 2.5 tonnes = 2.5 × 1000 = 2500kg
Hence, 2.5 tonnes = 2500kg
Class Activity:
(i) 1800ml (ii) 96cl (iii) 880ml (iv) 4.5m3
(i) 138mg (ii) 2480g (iii) 1.5g (iv) 0.28tonnes
Estimation of Other Things
Time
The base unit of time is second (s). Unlike length and mass, time does not follow the metric system of counting in base ten; but rather, the sexagessimal system (base 60) of the ancient Babylonian number system. The illustration is given below:
60 seconds = 1minute
60 minutes = 1 hour
24 hours = 1 day
7 days = 1week
52 weeks = 1 year
365¼ days = 1 year
366 days = 1 leap year
Examples:
(i) 5 minutes 45 seconds (ii) 2 hours 4 minutes 15 seconds
Solutions:
(i) 5 minutes 45 seconds to seconds
But, 1 minute = 60 seconds
Therefore, 5 minutes 45 seconds = (5 × 60secs) + 45 secs
= 300 + 45 = 345 secs
(ii) 2 hours 4 minutes 15 seconds
But 1 hour = 60 mins and 2 hours = 2 × 60 = 120 mins
Also, 1 minute = 60 secs,
Then 120 mins = 120 × 60 = 7200 secs
4 mins = 4 × 60 = 240 secs
Therefore, 2 hr 4mins 15 secs = 7200 + 240 + 15
= 745 seconds
(i) 2½ hours (ii) 500 secs
Solutions:
(i) 2½ hours to minutes
1 hour = 60 mins
Therefore, 2½ × 60 mins
5/2 × 60 = 5 × 30
= 150 minutes
(ii) 1200 secs to mins
But 60 secs = 1 min
Therefore, 1200secs = 1200 ÷ 60
= 20 mins.
Currency
Currency is the system or type of money used by a particular country.
Estimation is often used in market places and shops. People make good estimate of the cost of the article they want to buy while bargaining. The units of the Nigerian currency are Naira (₦) and kobo (k).
Example
Estimate and calculate the sum of the following amounts:
₦15.50, ₦1.75, ₦135.20, ₦18.10, and ₦12.20
Solution
Estimated Value
First step: Approximate the amounts to the nearest whole number;
₦16, ₦2, ₦135, ₦18, ₦12
Second step: Add them up;
₦16 + ₦2 + ₦135 + ₦18 + ₦12
= ₦183
Accurate Calculation
₦15.50k + ₦1.75k + ₦135.20k + ₦18.10k + ₦12.20k
= ₦182.75k
Estimation of Area
The basic unit of area is the square metre (sq. m or m2). However, smaller spaces are measured in centimetre (cm2) while larger spaces like states or countries are measured in acres, hectares and square kilometers (km2). The basic conversions are given below:
1 hectare = 10 000m2 = 100 acres
1m2 = 1m × 1m = (100 × 100)cm2
1m2 = 10 000cm2
1km2 = 1km × 1km
= 1000m × 1000m
= 1 000 000m2
2 000cm2 = 20001000m2
= 0.2 m2
Example
Estimate and calculate the number of tiles of size 15cm by 28cm that is needed for a square room which has an area of 4.9m2.
Solution
Estimated value:
Actual size of tile = 15cm by 28cm
≅ 20cm by 30cm
Area of the tiles = 20 × 30
= 600cm2
Area of square = 4.9m2
≅ 5m2
But 1m = 100cm
1m2 = (100 × 100) cm2
= 10 000 cm2
5m2 = 5 × 10 000 cm2
= 50 000 cm2
Number of tiles needed
= area of square roomarea of tiles
= 5000600
= 83.33 tiles
Accurate Calculation:
Area of tiles = 15 × 28
= 420cm2
Area of square room = 4.9m2 to cm2
= 4.9 × 10 000
= 49 000cm2
Number of tiles needed
= area of square roomarea of tiles
= 49000420
= 116.67
≅ 117 tiles
CLASS ACTIVITY
PRACTICE QUESTIONS
ASSIGNMENT
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